- Thank you received: 0
Measuring Stellar Object Velocity
15 years 2 days ago #23853
by PhilJ
Reply from Philip Janes was created by PhilJ
Geistkiesel,
You evidently don't understand the nature of simultaneity. Events that are simultaneous in one inertial frame are not simultaneous in another inertial frame. Saying that events are simultaneous in two frames does not make it so.
Fractal Foam Model of Universes: Creator
You evidently don't understand the nature of simultaneity. Events that are simultaneous in one inertial frame are not simultaneous in another inertial frame. Saying that events are simultaneous in two frames does not make it so.
Fractal Foam Model of Universes: Creator
Please Log in or Create an account to join the conversation.
- geistkiesel
- Offline
- New Member
Less
More
- Thank you received: 0
14 years 11 months ago #23911
by geistkiesel
Replied by geistkiesel on topic Reply from mike hernan
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by PhilJ</i>
<br />Geistkiesel,
You evidently don't understand the nature of simultaneity. Events that are simultaneous in one inertial frame are not simultaneous in another inertial frame. Saying that events are simultaneous in two frames does not make it so.
Fractal Foam Model of Universes: Creator
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
All events here are single event scenarios. Where does the simultaneity matter enter the discussion?
Mikey
<br />Geistkiesel,
You evidently don't understand the nature of simultaneity. Events that are simultaneous in one inertial frame are not simultaneous in another inertial frame. Saying that events are simultaneous in two frames does not make it so.
Fractal Foam Model of Universes: Creator
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
All events here are single event scenarios. Where does the simultaneity matter enter the discussion?
Mikey
Please Log in or Create an account to join the conversation.
14 years 11 months ago #23120
by Stoat
Replied by Stoat on topic Reply from Robert Turner
If the "speed" of gravity is vastly greater than the speed of light, then the whole non simultaneity becomes moot. An electron here and an electron on Vega say, are gravitationally, informationally, right up cheek by jowl with each other. The e.m information takes years to arrive.
Please Log in or Create an account to join the conversation.
- geistkiesel
- Offline
- New Member
Less
More
- Thank you received: 0
14 years 11 months ago #23124
by geistkiesel
Replied by geistkiesel on topic Reply from mike hernan
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Stoat</i>
<br />If the "speed" of gravity is vastly greater than the speed of light, then the whole non simultaneity becomes moot. An electron here and an electron on Vega say, are gravitationally, informationally, right up cheek by jowl with each other. The e.m information takes years to arrive.
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
I think I may have miscommunicated my thread to which I owe a correcion. Butt first a comment on your post. As a simple eample, the discovery of Neptune was relatred to poerturbations in Uranus' trajectory. Similarly, Pluto was discovered from perturbations in Neptunes orbit. The discovered perturbations, in other words, were limited to the distances between affected planets. The solar system is a microcosmic representatation of the concept that the force of gravity, already the weakest of all possible natural forces, must be limited in its effect by distance. I would be very surprised to discover your two electrons 'cheek to jowl' in any context of gravitational forces.
In any event, this thread started out very ugly, but I have since clarified the issues and cut some of the wordy fluff away. This system described here is able to determine the velocity of an inertial frame, regardless of various physical postulates having forbidden such an enterprise. The measurement is trivially simple.
Determine the velocity of an inertial frame using only three recorded time-of-flight events of a single light pulse.
***
WARNING IF YOU POST ANOTHER LINK LIKE THIS YOU WILL BE ASKED TO LEAVE
[moderator LB]
***
From the schematic of the system in Figure 1 measuring the velocity of the inertial frame A is clearly a very simple system. The A frame velocity is determined by a measurement of the distance a pulse of light travels in specific recorded time events. There are only three of these events: 1. the time the pulse was emitted from the A frame at t0, 2. the time the pulse arrived back at the A frame after reflection from the inertial frame transponder, Tp, at t1 and, 3. The arrival back at the A frames of the light pulse re-emitted at t1.
The distance difference, (d1 + d2) - (d3 + d4) is the distance the frame traveled during the total time-of-flight traveled by the light pulse. Picture the frame moving in the direction of the pulse moving away until the distance (d1 + d2) was traveled (project a straight line without the reflection). Attaching the final pulse trajectory to the end of the (d1 + d2) and heading toward the oncoming A frame, the collision of the pulse and the A frame determines the total distance traveled by the pulse and t2 duly notes this event.
The data base of experimental data is contained in the three time events, t0, t1, and t2. Expressing the dn in time and speed parameters with unit speed of light c = 1, then
(d1 + d2) - (d3 + d4) = [(t1 #8722; t0) #8722; (t2 #8722; t1)] = Va(t2 #8722; t0) or,
VA(t2 #8722; t0) = 2t1 #8722; (t2 + t0) hence,
VA = [2t1 #8722; (t2 + t0)]/(t2 #8722; t0) (1)
QED.
There is no referenced inertial frame to which the A frame VA is measured, or needs to be measured from and there is no absolute velocity reference frame where Vf = 0. Remember, the Va was not determined by a stop watch and meter stick. The Va is a calculated term using the known speed of light, the time-of-flight of pulse trajectory segments, and the definition of velocity. Can the origin of the light pulse be located and returned to? Yes, but there should be a valid reason for such a future activity sentimental reasons ought not to be consider a valid reason. If the Va becomes suspect, measure the velocity again, or simply maintain a constant velocity calculation and updating of the frame velocity for all tn.
V = (Xn+1 Xn)/(tn+1 tn). (2)
The question then is, does this measurement of velocity constitute a condition anticipated by the postulate of SRT that states,
It is impossible to measure or detect unaccelerated translatory motion in free space.?
Mikey
<br />If the "speed" of gravity is vastly greater than the speed of light, then the whole non simultaneity becomes moot. An electron here and an electron on Vega say, are gravitationally, informationally, right up cheek by jowl with each other. The e.m information takes years to arrive.
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
I think I may have miscommunicated my thread to which I owe a correcion. Butt first a comment on your post. As a simple eample, the discovery of Neptune was relatred to poerturbations in Uranus' trajectory. Similarly, Pluto was discovered from perturbations in Neptunes orbit. The discovered perturbations, in other words, were limited to the distances between affected planets. The solar system is a microcosmic representatation of the concept that the force of gravity, already the weakest of all possible natural forces, must be limited in its effect by distance. I would be very surprised to discover your two electrons 'cheek to jowl' in any context of gravitational forces.
In any event, this thread started out very ugly, but I have since clarified the issues and cut some of the wordy fluff away. This system described here is able to determine the velocity of an inertial frame, regardless of various physical postulates having forbidden such an enterprise. The measurement is trivially simple.
Determine the velocity of an inertial frame using only three recorded time-of-flight events of a single light pulse.
***
WARNING IF YOU POST ANOTHER LINK LIKE THIS YOU WILL BE ASKED TO LEAVE
[moderator LB]
***
From the schematic of the system in Figure 1 measuring the velocity of the inertial frame A is clearly a very simple system. The A frame velocity is determined by a measurement of the distance a pulse of light travels in specific recorded time events. There are only three of these events: 1. the time the pulse was emitted from the A frame at t0, 2. the time the pulse arrived back at the A frame after reflection from the inertial frame transponder, Tp, at t1 and, 3. The arrival back at the A frames of the light pulse re-emitted at t1.
The distance difference, (d1 + d2) - (d3 + d4) is the distance the frame traveled during the total time-of-flight traveled by the light pulse. Picture the frame moving in the direction of the pulse moving away until the distance (d1 + d2) was traveled (project a straight line without the reflection). Attaching the final pulse trajectory to the end of the (d1 + d2) and heading toward the oncoming A frame, the collision of the pulse and the A frame determines the total distance traveled by the pulse and t2 duly notes this event.
The data base of experimental data is contained in the three time events, t0, t1, and t2. Expressing the dn in time and speed parameters with unit speed of light c = 1, then
(d1 + d2) - (d3 + d4) = [(t1 #8722; t0) #8722; (t2 #8722; t1)] = Va(t2 #8722; t0) or,
VA(t2 #8722; t0) = 2t1 #8722; (t2 + t0) hence,
VA = [2t1 #8722; (t2 + t0)]/(t2 #8722; t0) (1)
QED.
There is no referenced inertial frame to which the A frame VA is measured, or needs to be measured from and there is no absolute velocity reference frame where Vf = 0. Remember, the Va was not determined by a stop watch and meter stick. The Va is a calculated term using the known speed of light, the time-of-flight of pulse trajectory segments, and the definition of velocity. Can the origin of the light pulse be located and returned to? Yes, but there should be a valid reason for such a future activity sentimental reasons ought not to be consider a valid reason. If the Va becomes suspect, measure the velocity again, or simply maintain a constant velocity calculation and updating of the frame velocity for all tn.
V = (Xn+1 Xn)/(tn+1 tn). (2)
The question then is, does this measurement of velocity constitute a condition anticipated by the postulate of SRT that states,
It is impossible to measure or detect unaccelerated translatory motion in free space.?
Mikey
Please Log in or Create an account to join the conversation.
14 years 11 months ago #23130
by evolivid
Replied by evolivid on topic Reply from Mark Baker
Hey Guys
I know this is on the topic but kinda off too .. do you think that you could use a laser and send it through a special telescope ... and get a picture from the edge of the laser where its traveling at the speed of light...
because they have listening devices that can do that ... may be using some sort of fiber optic to focus the light coming through the laser !
might be like a micro-telescope.
but the earth is spinning so would you get a curved view?
or would the line of site follow the edge of the laser ?
has any one kept up with what was going on with the sun pulses?
last time I seen any thing on it was last year.. a couple of days ago
on video
... Thanks
MARX
I know this is on the topic but kinda off too .. do you think that you could use a laser and send it through a special telescope ... and get a picture from the edge of the laser where its traveling at the speed of light...
because they have listening devices that can do that ... may be using some sort of fiber optic to focus the light coming through the laser !
might be like a micro-telescope.
but the earth is spinning so would you get a curved view?
or would the line of site follow the edge of the laser ?
has any one kept up with what was going on with the sun pulses?
last time I seen any thing on it was last year.. a couple of days ago
on video
... Thanks
MARX
Please Log in or Create an account to join the conversation.
14 years 11 months ago #23131
by Pluto
Replied by Pluto on topic Reply from
G'day
Seems very interesting, have to get my head over the maths.
Smile and live another day
Seems very interesting, have to get my head over the maths.
Smile and live another day
Please Log in or Create an account to join the conversation.
Time to create page: 0.534 seconds